RE: [ljc] A little Friday morning challenge for the group...

From: Jahan Z.
Sent on: Friday, January 25, 2013 11:57 AM

Assuming Math.random() returns a double between 0.0 and 1.0, Dan's solution is almost correct:

 

return (long)((max-min)*Math.random() + min)

 

should work, if I understood properly

 

Jahan

 

From: [address removed] [mailto:[address removed]] On Behalf Of Wesley Hall
Sent: 25 January[masked]:43
To: [address removed]
Subject: Re: [ljc] A little Friday morning challenge for the group...

 

Dan,

public static long generateRandom(long min, long max) {

        return (long)((max+1-min) * Math.random() + min);

    }

    public static void main(String[] args) {

        System.out.println(generateRandom(-1, Long.MAX_VALUE));

    }
}

When I run it I get values like...

[masked]

This, looks to me, to be less than the min boundary ;), so your solution doesn't work i'm afraid.

On Fri, Jan 25, 2013 at 11:20 AM, Dan Haywood <[address removed]> wrote:

return (max+1-min) * Math.random() + min



On 25 January[masked]:01, Wesley Hall <[address removed]> wrote:

Hello folks,

I came across what turned out to be a pretty interesting problem on a
project of mine last night, and I thought I would share it with you
guys. I am interested to see if anyone can come up with a better
solution than I did (highly likely I suspect :)).

Your mission, should you choose to accept it, is to write a method, in
Java, with the following signature...

public static long generateRandom(long min, long max) {
   // code here
}

Such that the method generates a random long value that is between the
two parameters provided (inclusive). The only restriction on the
parameters is that max >= min, for brevity you can assume this is
ensured outside of the method and that you don't need to check inside.

The first person to provide a working solution gets to look like a
hero... and if you provide a solution that I think is better than the
one I have, then I will (with your permission), use this version in
the library that I am about to open source and give you contributor
credit.

GO....

Wes




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