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Sunday Office Hours

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  • ak

    Aida, I forgot to add that the easiest way to get non-uniques is to use this comprehension: [x for x in mylist if mylist.count(x)>1]

    1 · September 28, 2014

  • @aaronchall

    So what do we want to talk about today?

    September 28, 2014

  • ak

    Is this going to be at the usual location?

    September 28, 2014

    • Jack M.

      If someone could post an address as well, I would really appreciate it.

      September 28, 2014

    • @aaronchall

      Yes, usual location!

      September 28, 2014

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