Re: [nycpython] question about list.insert()

From: Eric S.
Sent on: Saturday, August 14, 2010 4:30 AM
It's a design decision that mutating methods do not return self. It's so 
that you're forced to deal with them as mutators, and you don't 
accidentally (or through ignorance) assume they return a new list.

If you want to work around this, you can either create helper functions, 
or get more elaborate, such as this example: 
http://flylib.com...­

Eric.

On 8/13/10 11:00 PM, Jordan P wrote:
> hey nycpython,
>
>
> This is my first post to the group, though I've been a member for a while!
>
> I came across an interesting quirk in standard python regarding lists. I
> was in the middle of writing a beastly lambda expression and found
> myself having to insert a value at the beginning of a list. The design
> of my expression required that whatever call I made would have to return
> the list so that it could be used further up the chain.
>
> looking at the docs, I saw that list.insert(0, value) returns None, not
> the list.
>
> I was stuck for a good half hour until someone suggested I use: [val] +
> list instead. They warned, however, that this expression will cause a
> copy of list to be returned, not the original list. This stinks for
> efficiency.
>
> Can anybody come up with a reason why python's list methods (append,
> insert, extend, etc..) do not return the list? I'm using [val]+list for
> now, but would much rather not be making copies of all my lists.
>
>
> Looking forward to some interesting discussion--
> --Jordan
>
>
>
>
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-- 
Eric.

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