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Re: [ljc] A little Friday morning challenge for the group...

From: Dominic F.
Sent on: Friday, January 25, 2013 4:04 PM
Ignore my email. It came out long after I intended it to (approval delays :-)) and without testing it for the max and min values. Rookie mistake :-) Will take a crack at it until Sunday and get back.

Cheers
Dominic


On Fri, Jan 25, 2013 at 3:42 PM, Dominic Fernandes <[address removed]> wrote:
Hi Wesley,

Dan's solution will work with the right use of parentheses  as follows -

    public static long generateRandom(long min, long max)
    {
        return (long)((max - min + 1) * Math.random()) + min;   
    }

try it out and let me know.

Cheers
Dominic


On Fri, Jan 25, 2013 at 11:43 AM, Wesley Hall <[address removed]> wrote:
Dan,

public static long generateRandom(long min, long max) {

        return (long)((max+1-min) * Math.random() + min);

    }

    public static void main(String[] args) {

        System.out.println(generateRandom(-1, Long.MAX_VALUE));

    }
}

When I run it I get values like...

[masked]

This, looks to me, to be less than the min boundary ;), so your solution doesn't work i'm afraid.

On Fri, Jan 25, 2013 at 11:20 AM, Dan Haywood <[address removed]> wrote:
return (max+1-min) * Math.random() + min



On 25 January[masked]:01, Wesley Hall <[address removed]> wrote:
Hello folks,

I came across what turned out to be a pretty interesting problem on a
project of mine last night, and I thought I would share it with you
guys. I am interested to see if anyone can come up with a better
solution than I did (highly likely I suspect :)).

Your mission, should you choose to accept it, is to write a method, in
Java, with the following signature...

public static long generateRandom(long min, long max) {
   // code here
}

Such that the method generates a random long value that is between the
two parameters provided (inclusive). The only restriction on the
parameters is that max >= min, for brevity you can assume this is
ensured outside of the method and that you don't need to check inside.

The first person to provide a working solution gets to look like a
hero... and if you provide a solution that I think is better than the
one I have, then I will (with your permission), use this version in
the library that I am about to open source and give you contributor
credit.

GO....

Wes




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