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Re: [php-49] Type hinting exp4ect class if string is used?

From: Tim P.
Sent on: Tuesday, February 12, 2013 8:11 PM
Easy fix, just use magic comments

/* ohai newfag, make sure that $section is a string or all your base are belong to us */
public function setIniSection(string $section)

On Tue, Feb 12, 2013 at 10:18 AM, Jd Daniel <[address removed]> wrote:
Sounds familiar guys?

if I try public function setIniSection(string $section)
it expects a Class named string =( Any info? Code below even though it doesn't matter...

     * Cannibalize an Ini file and create definitions of a sub-selected content
     * @param   string $section   subsection of ini file
     * @return  definitions
    public function setIniSection($section)

        // fast primitive, because type hinting thinks string $section
        // means instanceof Class string =P Really PHP, really?
        if (!is_string($section)) trigger_error('Argument passed myst be of type string ' . gettype($section) . ' passed.');

        if (! file_exists(self::CONFIG_INI) {
            self::_throwException("Configuration Ini does not exist: " __DIR__ .'/' . self::CONFIG_INI);

        $iniArray = parse_ini_file((__DIR__ . '/' . self::CONFIG_INI), true);
        foreach ($iniArray[$section] as $definitor => $value) {
            if (!defined($definitor)) define($definitor, $value);

        return true;

Jd Daniel || ERADO
Senior Applications Architect
7901 Delridge Way SW #36D, Seattle

C.    [masked]

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