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Re: [php-49] sql error

From: Mike B.
Sent on: Monday, February 18, 2013 2:56 PM
It's not the cause of your problem, but it is bad form to use "SELECT *". You're probably getting more columns back than you're using, which is wasteful for I/O on disk and on the network. You're also referencing columns by name alter on, and your SQL statement will work even if those column names change, but your PHP will fail if they change.

... Mike

On Mon, Feb 18, 2013 at 1:43 PM, max steinmetz <[address removed]> wrote:
Hello, newb here with a question.

I'm attempting to build a simple shopping cart, this is my first time doing so and I am getting an error message which reads as follows:


Warning: mysql_fetch_assoc(): supplied argument is not a valid MySQL result resource in


Any help would be greatly appreciated as I'm google this error messag a bit and seen so many possible options that my mind turned to goop.

Again thank you for any help/direction possible.



This is the code starting with line #42

<div class="container">
<span class="top-label">
<span class="label-txt">PRODUCTS (TAKE Displayed things from here)</span>
</span>
<div class="content-area">
<div class="content drag-desired">
<?php
$result = mysql_query("SELECT * FROM internet_shop");
while($row=mysql_fetch_assoc($result))
{
echo '<div class="product"><img src="_img/products/'.$row['img'].'" alt="'.htmlspecialchars($row['name']).'" width="128" height="128" class="pngfix" /></div>';
}
?>
<div class="clear"></div>
</div>
</div>
<div class="bottom-container-border">
</div>
</div>





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